Saturday, September 12, 2009

Euler Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Powershell Solution:

  1. $SumOfSq = 1..100|%{[Math]::pow($_,2)}|measure -sum|%{$_.sum} 
  2. $SqOfSum = 1..100|measure -sum|%{[Math]::pow($_.sum,2)} 
  3. echo ($SqOfSum - $SumOfSq

Note: The solution may not be the optimized one… just a quick hack… I’ll revisit later for optimization if time permits… :-)

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